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Title register_volume42_issue51pdf Author acaulk Created Date ZA n d a re mo t e e n vi ro n me n t Hi g h l y e f f e ct i ve ma t h e ma t i cs cl a ssro o ms, wh e t h e r st u d e n t s a re 1 0 0 % p h ysi ca l l y p re se n t , 1 0 0 % d i g i t a l l y p re se n t o r a n ywh e re i n b e t we e n , a d h e re t o t h e sa me st ra t e g i e sNow we defineP Y i = 1{ith set of twins is MM} and X i = 1{ith set of twins is FF} Clearly n 1 = n i=1 Y i and n 2 = P n i=1 X i, and also Y iX i = 0 since a given set of twins cannot be both two males and two females Using these definitions, we have Cov(n 1,n 2) = En 1n 2−En 1En 2 = E i=1 Y i!
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F X (x) = 2 1 e x , – ∞ < x < ∞ (double exponential) b) Find the marginal probability density function of Y, f Y (y) f Y (y) = ∫ − − y y e y dx 2 1 = y e –y, 0 < y < ∞ θ(Gamma, α = 2, = 1) c) Are X and Y independent?A p p l i c a t i o n t o a d d t o y o u r L a n d l o r d a c c o u n t , f o l l o w t h e s t e p s a b o v e t o a d d m o r e a p p l i c a t i o n s t o y o u r a c c o u n t As s oc ia te your Tena nts ' Applic a tion(s ) with your La nd lor d Ac c ountY is measurable if f 1(B) 2Afor every B2B Note that the measurability of a function depends only on the ˙algebras;
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If P(AB) = P(A) Ex) Probability that card drawn in event A is a Jack given event B was the drawing of a red card Pr(AB) = Pr(𝐴∩𝐵) Pr (𝐵) = 2 52 26/52 = 1/13 It was stated that if A and B are mutually exclusive > (A∩B) = 0 then A and B are never independent Various examples were then given to demonstrate independent events(a) P(Y = 3) = (i) 0 (ii) 025 (iii) 050 (iv) 075 (b) P(Y 3) = F(3) = R 3 2 x 6 dx= x 2 12 i x=3 x=2 = 3 12 2 12 = 5 12 requires (i) summation (ii) integration and is a value of a (i) probability density function (ii) cumulative distribution function which is a (i) stepwise (ii) smooth increasing function (c) E(Y) = (i) P yf(y) (ii) R yf(y)dy1 Suppose that the joint pdf of X and Y is given by f(x,y) = 8xy, 0 < x < y < 1 = 0 elsewhere (a) Verify that the f(x,y) given above is indeed a pdf Answer Z 1 0 Z y 0 8xydxdy = Z 1 0 4yx2y 0 dy = Z 1 0 4y3dy = y41 0 = 1 So, f(x,y) is a pdf (b) Find the marginal probability density of X, f 1(x) Answer f 1(x) = Z 1 x 8xydy = 4xy2
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